3.2.29 \(\int x^4 \sinh ^{-1}(a x)^n \, dx\) [129]

Optimal. Leaf size=173 \[ \frac {5^{-1-n} \left (-\sinh ^{-1}(a x)\right )^{-n} \sinh ^{-1}(a x)^n \Gamma \left (1+n,-5 \sinh ^{-1}(a x)\right )}{32 a^5}-\frac {3^{-n} \left (-\sinh ^{-1}(a x)\right )^{-n} \sinh ^{-1}(a x)^n \Gamma \left (1+n,-3 \sinh ^{-1}(a x)\right )}{32 a^5}+\frac {\left (-\sinh ^{-1}(a x)\right )^{-n} \sinh ^{-1}(a x)^n \Gamma \left (1+n,-\sinh ^{-1}(a x)\right )}{16 a^5}-\frac {\Gamma \left (1+n,\sinh ^{-1}(a x)\right )}{16 a^5}+\frac {3^{-n} \Gamma \left (1+n,3 \sinh ^{-1}(a x)\right )}{32 a^5}-\frac {5^{-1-n} \Gamma \left (1+n,5 \sinh ^{-1}(a x)\right )}{32 a^5} \]

[Out]

1/32*5^(-1-n)*arcsinh(a*x)^n*GAMMA(1+n,-5*arcsinh(a*x))/a^5/((-arcsinh(a*x))^n)-1/32*arcsinh(a*x)^n*GAMMA(1+n,
-3*arcsinh(a*x))/(3^n)/a^5/((-arcsinh(a*x))^n)+1/16*arcsinh(a*x)^n*GAMMA(1+n,-arcsinh(a*x))/a^5/((-arcsinh(a*x
))^n)-1/16*GAMMA(1+n,arcsinh(a*x))/a^5+1/32*GAMMA(1+n,3*arcsinh(a*x))/(3^n)/a^5-1/32*5^(-1-n)*GAMMA(1+n,5*arcs
inh(a*x))/a^5

________________________________________________________________________________________

Rubi [A]
time = 0.16, antiderivative size = 173, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 4, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {5780, 5556, 3388, 2212} \begin {gather*} \frac {5^{-n-1} \sinh ^{-1}(a x)^n \left (-\sinh ^{-1}(a x)\right )^{-n} \text {Gamma}\left (n+1,-5 \sinh ^{-1}(a x)\right )}{32 a^5}-\frac {3^{-n} \sinh ^{-1}(a x)^n \left (-\sinh ^{-1}(a x)\right )^{-n} \text {Gamma}\left (n+1,-3 \sinh ^{-1}(a x)\right )}{32 a^5}+\frac {\sinh ^{-1}(a x)^n \left (-\sinh ^{-1}(a x)\right )^{-n} \text {Gamma}\left (n+1,-\sinh ^{-1}(a x)\right )}{16 a^5}-\frac {\text {Gamma}\left (n+1,\sinh ^{-1}(a x)\right )}{16 a^5}+\frac {3^{-n} \text {Gamma}\left (n+1,3 \sinh ^{-1}(a x)\right )}{32 a^5}-\frac {5^{-n-1} \text {Gamma}\left (n+1,5 \sinh ^{-1}(a x)\right )}{32 a^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^4*ArcSinh[a*x]^n,x]

[Out]

(5^(-1 - n)*ArcSinh[a*x]^n*Gamma[1 + n, -5*ArcSinh[a*x]])/(32*a^5*(-ArcSinh[a*x])^n) - (ArcSinh[a*x]^n*Gamma[1
+ n, -3*ArcSinh[a*x]])/(32*3^n*a^5*(-ArcSinh[a*x])^n) + (ArcSinh[a*x]^n*Gamma[1 + n, -ArcSinh[a*x]])/(16*a^5*
(-ArcSinh[a*x])^n) - Gamma[1 + n, ArcSinh[a*x]]/(16*a^5) + Gamma[1 + n, 3*ArcSinh[a*x]]/(32*3^n*a^5) - (5^(-1
- n)*Gamma[1 + n, 5*ArcSinh[a*x]])/(32*a^5)

Rule 2212

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> Simp[(-F^(g*(e - c*(f/d))))*((c
+ d*x)^FracPart[m]/(d*((-f)*g*(Log[F]/d))^(IntPart[m] + 1)*((-f)*g*Log[F]*((c + d*x)/d))^FracPart[m]))*Gamma[m
+ 1, ((-f)*g*(Log[F]/d))*(c + d*x)], x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rule 3388

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/(E^(
I*k*Pi)*E^(I*(e + f*x))), x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*k*Pi)*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d
, e, f, m}, x] && IntegerQ[2*k]

Rule 5556

Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int
[ExpandTrigReduce[(c + d*x)^m, Sinh[a + b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n,
0] && IGtQ[p, 0]

Rule 5780

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Dist[1/(b*c^(m + 1)), Subst[Int[x^n*Sinh
[-a/b + x/b]^m*Cosh[-a/b + x/b], x], x, a + b*ArcSinh[c*x]], x] /; FreeQ[{a, b, c, n}, x] && IGtQ[m, 0]

Rubi steps

\begin {align*} \int x^4 \sinh ^{-1}(a x)^n \, dx &=\frac {\text {Subst}\left (\int x^n \cosh (x) \sinh ^4(x) \, dx,x,\sinh ^{-1}(a x)\right )}{a^5}\\ &=\frac {\text {Subst}\left (\int \left (\frac {1}{8} x^n \cosh (x)-\frac {3}{16} x^n \cosh (3 x)+\frac {1}{16} x^n \cosh (5 x)\right ) \, dx,x,\sinh ^{-1}(a x)\right )}{a^5}\\ &=\frac {\text {Subst}\left (\int x^n \cosh (5 x) \, dx,x,\sinh ^{-1}(a x)\right )}{16 a^5}+\frac {\text {Subst}\left (\int x^n \cosh (x) \, dx,x,\sinh ^{-1}(a x)\right )}{8 a^5}-\frac {3 \text {Subst}\left (\int x^n \cosh (3 x) \, dx,x,\sinh ^{-1}(a x)\right )}{16 a^5}\\ &=\frac {\text {Subst}\left (\int e^{-5 x} x^n \, dx,x,\sinh ^{-1}(a x)\right )}{32 a^5}+\frac {\text {Subst}\left (\int e^{5 x} x^n \, dx,x,\sinh ^{-1}(a x)\right )}{32 a^5}+\frac {\text {Subst}\left (\int e^{-x} x^n \, dx,x,\sinh ^{-1}(a x)\right )}{16 a^5}+\frac {\text {Subst}\left (\int e^x x^n \, dx,x,\sinh ^{-1}(a x)\right )}{16 a^5}-\frac {3 \text {Subst}\left (\int e^{-3 x} x^n \, dx,x,\sinh ^{-1}(a x)\right )}{32 a^5}-\frac {3 \text {Subst}\left (\int e^{3 x} x^n \, dx,x,\sinh ^{-1}(a x)\right )}{32 a^5}\\ &=\frac {5^{-1-n} \left (-\sinh ^{-1}(a x)\right )^{-n} \sinh ^{-1}(a x)^n \Gamma \left (1+n,-5 \sinh ^{-1}(a x)\right )}{32 a^5}-\frac {3^{-n} \left (-\sinh ^{-1}(a x)\right )^{-n} \sinh ^{-1}(a x)^n \Gamma \left (1+n,-3 \sinh ^{-1}(a x)\right )}{32 a^5}+\frac {\left (-\sinh ^{-1}(a x)\right )^{-n} \sinh ^{-1}(a x)^n \Gamma \left (1+n,-\sinh ^{-1}(a x)\right )}{16 a^5}-\frac {\Gamma \left (1+n,\sinh ^{-1}(a x)\right )}{16 a^5}+\frac {3^{-n} \Gamma \left (1+n,3 \sinh ^{-1}(a x)\right )}{32 a^5}-\frac {5^{-1-n} \Gamma \left (1+n,5 \sinh ^{-1}(a x)\right )}{32 a^5}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]
time = 0.10, size = 145, normalized size = 0.84 \begin {gather*} \frac {5^{-n} \left (-\sinh ^{-1}(a x)\right )^{-n} \sinh ^{-1}(a x)^n \Gamma \left (1+n,-5 \sinh ^{-1}(a x)\right )-5\ 3^{-n} \left (-\sinh ^{-1}(a x)\right )^{-n} \sinh ^{-1}(a x)^n \Gamma \left (1+n,-3 \sinh ^{-1}(a x)\right )+10 \left (-\sinh ^{-1}(a x)\right )^{-n} \sinh ^{-1}(a x)^n \Gamma \left (1+n,-\sinh ^{-1}(a x)\right )-10 \Gamma \left (1+n,\sinh ^{-1}(a x)\right )+5\ 3^{-n} \Gamma \left (1+n,3 \sinh ^{-1}(a x)\right )-5^{-n} \Gamma \left (1+n,5 \sinh ^{-1}(a x)\right )}{160 a^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^4*ArcSinh[a*x]^n,x]

[Out]

((ArcSinh[a*x]^n*Gamma[1 + n, -5*ArcSinh[a*x]])/(5^n*(-ArcSinh[a*x])^n) - (5*ArcSinh[a*x]^n*Gamma[1 + n, -3*Ar
cSinh[a*x]])/(3^n*(-ArcSinh[a*x])^n) + (10*ArcSinh[a*x]^n*Gamma[1 + n, -ArcSinh[a*x]])/(-ArcSinh[a*x])^n - 10*
Gamma[1 + n, ArcSinh[a*x]] + (5*Gamma[1 + n, 3*ArcSinh[a*x]])/3^n - Gamma[1 + n, 5*ArcSinh[a*x]]/5^n)/(160*a^5
)

________________________________________________________________________________________

Maple [F]
time = 1.90, size = 0, normalized size = 0.00 \[\int x^{4} \arcsinh \left (a x \right )^{n}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*arcsinh(a*x)^n,x)

[Out]

int(x^4*arcsinh(a*x)^n,x)

________________________________________________________________________________________

Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*arcsinh(a*x)^n,x, algorithm="maxima")

[Out]

integrate(x^4*arcsinh(a*x)^n, x)

________________________________________________________________________________________

Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*arcsinh(a*x)^n,x, algorithm="fricas")

[Out]

integral(x^4*arcsinh(a*x)^n, x)

________________________________________________________________________________________

Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{4} \operatorname {asinh}^{n}{\left (a x \right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4*asinh(a*x)**n,x)

[Out]

Integral(x**4*asinh(a*x)**n, x)

________________________________________________________________________________________

Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*arcsinh(a*x)^n,x, algorithm="giac")

[Out]

integrate(x^4*arcsinh(a*x)^n, x)

________________________________________________________________________________________

Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int x^4\,{\mathrm {asinh}\left (a\,x\right )}^n \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*asinh(a*x)^n,x)

[Out]

int(x^4*asinh(a*x)^n, x)

________________________________________________________________________________________